Difference between revisions of "C оператори"

From Ilianko
 
(2 intermediate revisions by the same user not shown)
Line 9: Line 9:
 
  ++a <=> a = a + 1 ; --a <=> a = a - 1
 
  ++a <=> a = a + 1 ; --a <=> a = a - 1
 
</pre></code>
 
</pre></code>
 +
 +
<code><pre>
 +
#include <stdio>
 +
 +
int main()
 +
{
 +
  int a = 1, b = 2;
 +
 +
  a++;
 +
  printf(" a = %i \n" , a);
 +
  printf(" a++ = %i \n" , a++);
 +
  printf(" ++a = %i \n" , ++a);
 +
 +
  a = 1; b = 2;
 +
  a = b++; //  <=>  a = b; b = b + 1;
 +
  printf("a = b++; b = %i \n" , b);
 +
  printf("a = b++; a = %i \n" , a);
 +
 +
  a = ++b; //  <=>  b = b + 1; a = a;
 +
  printf("a = ++b; b = %i \n" , b);
 +
  printf("a = ++b; a = %i \n" , a);
 +
 +
  return 0;
 +
}
 +
</code></pre>
  
 
== Сравнителни <code>== != > < >= <= </code> ==
 
== Сравнителни <code>== != > < >= <= </code> ==

Latest revision as of 09:34, 23 March 2011

Математически + - * / %

 int a = 1, b = 2;
 a + b  = 3;
 a - b = -1;
 a * b = 2;
 a / b = 0; 
 a % b = 1
 ++a <=> a = a + 1 ; --a <=> a = a - 1
#include <stdio>

int main()
{
  int a = 1, b = 2;
	
  a++;
  printf(" a = %i \n" , a);
  printf(" a++ = %i \n" , a++);
  printf(" ++a = %i \n" , ++a);
	
  a = 1; b = 2;
  a = b++; //  <=>  a = b; b = b + 1;
  printf("a = b++; b = %i \n" , b);
  printf("a = b++; a = %i \n" , a);
	
  a = ++b; //  <=>  b = b + 1; a = a;
  printf("a = ++b; b = %i \n" , b);
  printf("a = ++b; a = %i \n" , a);
	
  return 0;
}
</code>

Сравнителни == != > < >= <=

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[Оператори в C и C++]