Difference between revisions of "Махало на Капица"
From Ilianko
| Line 4: | Line 4: | ||
<m>|(\bar{z})^n| = |z|^n </m> | <m>|(\bar{z})^n| = |z|^n </m> | ||
| + | |||
<m> \arg(z^n) = n \arg(z) </m> | <m> \arg(z^n) = n \arg(z) </m> | ||
[[Category:Matlab]] | [[Category:Matlab]] | ||
Revision as of 13:39, 31 May 2011
<m> |\bar{z}| = |z| </m>
<m>|(\bar{z})^n| = |z|^n </m>
<m> \arg(z^n) = n \arg(z) </m>
